#mysql
06 October 2007
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23:56 <****> bigfleet, subquery solution: select members.id, (select COUNT(*) from trades where trades.member_id= members.id)
23:57 <****> bigfleet, here is bar a derived table: select * from (select a from foo) as bar
23:57 <****> gnari: Wow, that first one looks promising
23:58 <****> and on and on.
23:59 <****> bigfleet: There's more to it, but that shows the basic form.
--- Log closed Sun Oct 07 00:00:57 2007
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